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Home/ Questions/Q 8484793
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T20:28:18+00:00 2026-06-10T20:28:18+00:00

How can I print the values being sent to the sqlite database while using

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How can I print the values being sent to the sqlite database while using Core Data SQL Debug?

Using the “-com.apple.CoreData.SQLDebug 1” in my “Arguments Passed on Launch” debug options prints the SQL structure just fine

(you can check see how to use this here: XCode4 and Core Data: How to enable SQL Debugging)

But the problem is that the NSLog printed is something like UPDATE ZTABLE SET ZCOLUMN = ? WHERE ZID = ? and it does not help at all if you are trying to see what is the full SQL statement and/or data being sent to the database.

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  1. Editorial Team
    Editorial Team
    2026-06-10T20:28:19+00:00Added an answer on June 10, 2026 at 8:28 pm

    Open “Product -> Scheme -> Edit Scheme…” in Xcode and add
    to “Arguments Passed on Launch”:

    -com.apple.CoreData.SQLDebug 3
    -com.apple.CoreData.Logging.stderr 1 
    

    (The second launch argument is needed for Core Data debugging on
    iOS 10/macOS 10.12 or later, see com.apple.CoreData.SQLDebug not working for more information.)

    The you’ll see all the values that the SQL statements are bound to.
    Example output:

    test56[1588:c07] CoreData: sql: BEGIN EXCLUSIVE
    test56[1588:c07] CoreData: sql: INSERT INTO ZEVENT(Z_PK, Z_ENT, Z_OPT, ZTIMESTAMP) VALUES(?, ?, ?, ?)
    test56[1588:c07] CoreData: details: SQLite bind[0] = (int64)13
    test56[1588:c07] CoreData: details: SQLite bind[1] = (int64)1
    test56[1588:c07] CoreData: details: SQLite bind[2] = (int64)1
    test56[1588:c07] CoreData: details: SQLite bind[3] = "368650709.435904"
    test56[1588:c07] CoreData: sql: COMMIT
    
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