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Asked: May 10, 20262026-05-10T20:48:16+00:00 2026-05-10T20:48:16+00:00

How do I create a directory at a given path, and also create any

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How do I create a directory at a given path, and also create any missing parent directories along that path? For example, the Bash command mkdir -p /path/to/nested/directory does this.

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  1. 2026-05-10T20:48:17+00:00Added an answer on May 10, 2026 at 8:48 pm

    On Python ≥ 3.5, use pathlib.Path.mkdir:

    from pathlib import Path Path('/my/directory').mkdir(parents=True, exist_ok=True) 

    For older versions of Python, I see two answers with good qualities, each with a small flaw, so I will give my take on it:

    Try os.path.exists, and consider os.makedirs for the creation.

    import os if not os.path.exists(directory):     os.makedirs(directory) 

    As noted in comments and elsewhere, there’s a race condition – if the directory is created between the os.path.exists and the os.makedirs calls, the os.makedirs will fail with an OSError. Unfortunately, blanket-catching OSError and continuing is not foolproof, as it will ignore a failure to create the directory due to other factors, such as insufficient permissions, full disk, etc.

    One option would be to trap the OSError and examine the embedded error code (see Is there a cross-platform way of getting information from Python’s OSError):

    import os, errno  try:     os.makedirs(directory) except OSError as e:     if e.errno != errno.EEXIST:         raise 

    Alternatively, there could be a second os.path.exists, but suppose another created the directory after the first check, then removed it before the second one – we could still be fooled.

    Depending on the application, the danger of concurrent operations may be more or less than the danger posed by other factors such as file permissions. The developer would have to know more about the particular application being developed and its expected environment before choosing an implementation.

    Modern versions of Python improve this code quite a bit, both by exposing FileExistsError (in 3.3+)…

    try:     os.makedirs('path/to/directory') except FileExistsError:     # directory already exists     pass 

    …and by allowing a keyword argument to os.makedirs called exist_ok (in 3.2+).

    os.makedirs('path/to/directory', exist_ok=True)  # succeeds even if directory exists. 
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