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Home/ Questions/Q 494193
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T05:28:29+00:00 2026-05-13T05:28:29+00:00

How do I get the array to increment to the next row? I am

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How do I get the array to increment to the next row? I am making a table of labels 3 wide and ten high. The result that I am getting is three repeats in each row. How can I bump to the next row for each table cell.

$i =0;
for ($i = 1; $i <= 3; ++$i){
while($row = mysql_fetch_array($result)){

$company = $row['company'];
$comp_strt = $row['comp_strt'];
$comp_city = $row['comp_city'];
$comp_state = $row['comp_state'];
$comp_zip = $row['comp_zip'];
$celldata= $company."<br>".$comp_strt."<br>".$comp_city.",&nbsp;".$comp_state."&nbsp;".$comp_zip;
if($i = 1){echo "<tr style='row-height: 5em;'><td>'".$celldata."'</td>";}
if($i = 2){echo "<td>'".$celldata."'</td>";}
if($i = 3){echo "<td>'".$celldata."'</td></tr>"; $i = 1;}
}}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T05:28:29+00:00Added an answer on May 13, 2026 at 5:28 am

    I would do this:

    $cellsPerRow = 3;
    $i = 0;
    echo '<table>';
    while ($row = mysql_fetch_array($result)) {
        if ($i % $cellsPerRow == 0) {
            echo '<tr>';
        }
    
        // process $row and echo the table cell
    
        if ($i % $cellsPerRow == $cellsPerRow - 1) {
            echo '</tr>';
        }
        $i++;
    }
    if ($i > 0 && $i % $cellsPerRow != 0) { // finish off row if needed
        while ($i % $cellsPerRow != 0) {
            echo '<td></td>';
            $i++;
        }
        echo '</tr>';
    }
    echo '</table>';
    

    This will always give you a proper table.

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