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Home/ Questions/Q 735597
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T07:30:31+00:00 2026-05-14T07:30:31+00:00

How does one suppress the automatic initialization and destruction of a type? While it

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How does one suppress the automatic initialization and destruction of a type? While it is wonderful that T buffer[100] automatically initializes all the elements of buffer, and destroys them when they fall out of scope, this is not the behavior I want.

#include <iostream>

static int created   = 0,
           destroyed = 0;

struct S
{
    S()
    {
        ++created;
    }
    ~S()
    {
        ++destroyed;
    }
};

template <typename T, size_t KCount>
class fixed_vector
{
private:
    T m_buffer[KCount];
public:
    fixed_vector()
    {
        // some way to suppress the automatic initialization of m_buffer
    }

    ~fixed_vector()
    {
        // some way to suppress the automatic destruction of m_buffer
    }
};

int main()
{
    {
        fixed_vector<S, 100> arr;
    }

    std::cout << "Created:\t"   << created   << std::endl;
    std::cout << "Destroyed:\t" << destroyed << std::endl;
    return 0;
}

The output of this program is:

Created:    100
Destroyed:  100

I would like it to be:

Created:    0
Destroyed:  0

My only idea is to make m_buffer some trivially constructed and destructed type like char and then rely on operator[] to wrap the pointer math for me, although this seems like a horribly hacked solution. Another solution would be to use malloc and free, but that gives a level of indirection that I do not want.


The reason why I want this is because I am making a container and I do not want to pay for the initialization overhead of things that I will not use. For example, if my main function was:

int main()
{
    {
        std::vector<S> vec;
        vec.reserve(50);
    }

    std::cout << "Created:\t"   << created   << std::endl;
    std::cout << "Destroyed:\t" << destroyed << std::endl;
    return 0;
}

The output would be correct:

Created:    0
Destroyed:  0
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T07:30:31+00:00Added an answer on May 14, 2026 at 7:30 am

    You can create the array as array of chars and then use placement new to create the elements when needed.

    template <typename T, size_t KCount>
    class Array
    {
    private:
        char m_buffer[KCount*sizeof(T)]; // TODO make sure it's aligned correctly
    
        T operator[](int i) {
            return reinterpret_cast<T&>(m_buffer[i*sizeof(T)]);
        }
    

    After re-reading your question it seems that you want a sparse array, this sometimes goes by the name of map ;o) (of course the performance characteristics are different…)

    template <typename T, size_t KCount>
    class SparseArray {
        std::map<size_t, T> m_map;
    public:
        T& operator[](size_t i) {
            if (i > KCount)
                throw "out of bounds";
            return m_map[i];
        }
    
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