Question

How to declare array of strings in C.
Is it like

char str[100][100] ={"this","that","those"};

If so how to access the values .. can i travers like this?
(It does not give any compilation error ..but shows some additional garbage characters)

int i ,j;
char  c[100][100] = {"this","that"};
for(i = 0 ;c[i] != '\0';++i)
 for(j = 0; c[i][j] != '\0';++j)
   printf("%c",c[i][j]);

Is it necessary to add ‘\0’ at end of eac string..for ex:

 char c[100][100]={"this\0","that\0"}

Answer 1

How to declare array of strings in C

It is Ok, but you will have to be extremely careful of buffer-overflow when dealing with these strings

can i travers like this?

Note that the condition in the first for loop: for(i = 0 ;c[i] != '\0';++i) is probably wrong, and will fail since c[i] is an array, whose address is not 0. You should probably iterate the outer array by numbers [until you read all elements], and not until you find some specific character. You can do that by maintaining a different variable n, which will indicate how many elements does the array currently have.

Is it necessary to add ‘\0’ at end of eac string..for ex:

No – the compiler add it to you, it is just fine without adding the '\0' to the string.