Question

How to make a specialisation for a template function with returning value template?

I tried this:

myfunc.h:

#pragma once

template< >
int MyFunc<int>(){
   return 10;
}

main.cpp:

#include "myfunc.h"

int main()
{
    int a;
    a = MyFunc<int>();
    return 0;
}

but i have error: expected initializer before ‘<‘ token

Answer 1

You are missing the primary template before you declare your specialization.

template<typename> int func() { return 42; }

template<> int func<int>() { return 23; }

Please be aware of the problems of function specializations.