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Asked: 2026-06-18T14:38:19+00:00

How would I go about generating a sequential alphanumeric string? Each string should only

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How would I go about generating a sequential alphanumeric string?

Each string should only be 8 characters.

The characters possible for each position are:

["0", "1", "2", "3", "4", "5", "6", "7", "8", "9", "B", "C", "D", "F", "G", "H", "J", "K", "L", "M", "N", "P", "Q", "R", "S", "T", "V", "W", "X", "Y", "Z"]

Also, If possible I would like to choose the starting point of the sequence.

For example:

00000001
00000002
00000003
00000005
...
0000L3FH
0000L3FJ
0000L3FK
0000L3FL
0000L3FM
0000L3FN
0000L3FP
...
0000L4FP
0000L4FQ
0000L4FR
0000L4FS
...
0000M000
0000M001
0000M002
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1 Answer

  1. Editorial Team

    That is a permutation with repetition. Arrays can do that out of the box.

    chars = %w(0 1 2 B C)
sequencer = chars.repeated_permutation(chars.size) #OP:replace chars.size by 8
10.times{p sequencer.next}
#["0", "0", "0", "0", "0"]
#["0", "0", "0", "0", "1"]
#["0", "0", "0", "0", "2"]
#["0", "0", "0", "0", "B"]
#["0", "0", "0", "0", "C"]
#["0", "0", "0", "1", "0"]
#["0", "0", "0", "1", "1"]
#["0", "0", "0", "1", "2"]
#["0", "0", "0", "1", "B"]
#["0", "0", "0", "1", "C"]

p sequencer.next
#["0", "0", "0", "2", "0"]
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