Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8950197
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 15, 20262026-06-15T13:23:58+00:00 2026-06-15T13:23:58+00:00

How would I parse the two numbers in the following string: String fName =

  • 0

How would I parse the two numbers in the following string:

String fName = "Run_1_vs_2_pw_optimal_mapping.txt";

I tried it like this, but it doesn’t work:

    Pattern filePatt = Pattern.compile("Run_(\\d+)_vs_(\\d+)_", Pattern.CASE_INSENSITIVE);

    Matcher scanner = this.filePatt.matcher(fName);
    while (scanner.find()) {
            int groupSize = scanner.groupCount();
            if (groupSize == 2) {
                firstRun = Integer.parseInt(scanner.group(0));
                secondRun = Integer.parseInt(scanner.group(1));
            }
            break;
     }

However, this doesn’t work, because scanner.group(0) returns Run_1_vs_2. But why?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-15T13:23:59+00:00Added an answer on June 15, 2026 at 1:23 pm

    See the documentation.

    Capturing groups are indexed from left to right, starting at one. Group zero denotes the entire pattern, so the expression m.group(0) is equivalent to m.group().

    Use group(1) and group(2).

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I am getting json response like this {item_id:1,item_title:Item 1}{item_id:2,item_title:Item 2} how would I parse
I would like to parse the following text into formatted URLs with anchor tags:
I would like to parse free-text time intervals like the following, using Python: 1
I would like to convert data.txt into scheme list using sed into the following
How would I parse a domain name in Objective-C? For example if my string
Would like to parse IPv4 address from exit-addresses . Format of the file: ExitNode
I would like to parse the folder name and file name from passed argument.
I would like to parse the values from aspx pages, both what is passed
I would like to parse through and display and picture and description for each
I have a text file and I would like to parse it using regular

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.