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Home/ Questions/Q 68125
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Asked: May 10, 20262026-05-10T19:22:03+00:00 2026-05-10T19:22:03+00:00

I am declaring an array of void pointers. Each of which points to a

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I am declaring an array of void pointers. Each of which points to a value of arbitary type.
void **values; // Array of void pointers to each value of arbitary type

Initializing values as follows:

     values = (void**)calloc(3,sizeof(void*));     //can initialize values as: values = new void* [3];     int ival = 1;     float fval = 2.0;     char* str = 'word';     values[0] = (void*)new int(ival);     values[1] = (void*)new float(fval);     values[2] = (void*)str;      //Trying to Clear the memory allocated     free(*values);      //Error: *** glibc detected *** simpleSQL: free(): invalid pointer: 0x080611b4     //Core dumped     delete[] values*;     //warning: deleting 'void*' is undefined     //Similar Error. 

Now how do I free/delete the memory allocated for values ( the array of void pointers)?

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1 Answer

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  1. 2026-05-10T19:22:04+00:00Added an answer on May 10, 2026 at 7:22 pm

    You have 3 things that are dynamically allocated that need to be freed in 2 different ways:

    delete reinterpret_cast<int*>( values[0]);     delete reinterpret_cast<float*>( values[1]);  free( values); // I'm not sure why this would have failed in your example,                 //    but it would have leaked the 2 items that you allocated                 //    with new 

    Note that since str is not dynamically allocated it should not (actually cannot) be freed.

    A couple of notes:

    • I’m assuming that the sizeof(void) was meant to be sizeof(void*) since what you have won’t compile
    • I’m not going to say anything about your seemingly random casting except that it looks like code that ready for disaster in general
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