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Home/ Questions/Q 8983125
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T20:45:30+00:00 2026-06-15T20:45:30+00:00

I am defining a boost multiindex container: namespace bmi = boost::multi_index; struct DijkstraTriplet {

  • 0

I am defining a boost multiindex container:

namespace bmi = boost::multi_index;
struct DijkstraTriplet {
...
};

typedef multi_index_container <
  DijkstraTriplet,
  bmi::indexed_by<
    bmi::ordered_unique<bmi::member<DijkstraTriplet,size_t,&DijkstraTriplet::linkId> >,
    bmi::ordered_non_unique<bmi::identity<DijkstraTriplet> >
 >
> DijkstraTripletContainer;

at some point I am filling it with data and would like to scan one of its indexes. For that purpose I define an iterator:

DijkstraTripletContainer::nth_index<0>::type::iterator it;

(using an old compiler). This is incredibly long and awkward. To make it shorter and more readable I added those lines:

#define dtt0 DijkstraTripletContainer::nth_index<0>::type
#define dtt1 DijkstraTripletContainer::nth_index<1>::type

and then used dtt0::iterator (which is elegantly short, but at the same time ugly, because expressed in terms of #defines). Is there a more elegant way to have a shortcut without #defines? I am looking something as elegant as

namespace bmi = boost::multi_index;

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  1. Editorial Team
    Editorial Team
    2026-06-15T20:45:32+00:00Added an answer on June 15, 2026 at 8:45 pm
    typedef DijkstraTripletContainer::nth_index<0>::type dtt0;
    
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