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Home/ Questions/Q 6758215
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T13:45:17+00:00 2026-05-26T13:45:17+00:00

i am developing sparklr application i changed xml to <bean id=tokenServices class=org.springframework.security.oauth2.provider.token.JdbcOAuth2ProviderTokenServices> <property name=supportRefreshToken

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i am developing sparklr application i changed xml to

<bean id="tokenServices" class="org.springframework.security.oauth2.provider.token.JdbcOAuth2ProviderTokenServices">
        <property name="supportRefreshToken" value="true" />
        <constructor-arg index="0" ref="dataSource" />

    </bean>

i take an error at client side
Exception in thread “main” java.io.IOException: PreparedStatementCallback; bad SQL grammar [insert into oauth_access_token (token_id, token, authentication, refresh_token) values (?, ?, ?, ?)]; nested exception is com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Table ‘authantication.oauth_access_token’ doesn’t exist
at javaapplication17.RestClient.httpPost(RestClient.java:74)
at javaapplication17.Main.main(Main.java:19)
Java Result: 1

but ı have this column on db,instead of using org.springframework.security.oauth2.provider.token.JdbcOAuth2ProviderTokenServices”

i need to develop my own class,but i cant developed it gives error is there any example
please help me!!

thank you

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  1. Editorial Team
    Editorial Team
    2026-05-26T13:45:18+00:00Added an answer on May 26, 2026 at 1:45 pm

    The exception tells you the table oauth_access_token doesn’t exist

    Making this work with hibernate is harder (I’ve been working on it for a couple of days, perhaps I’ll blog about it sometime soon). If you are unsure how to proceed, stick to the JDBC version and just make sure the table exists

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