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Home/ Questions/Q 7969103
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T07:11:05+00:00 2026-06-04T07:11:05+00:00

I am editing someone’s code and I don’t understand what they are trying to

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I am editing someone’s code and I don’t understand what they are trying to do with this statement. This is at the end of the function.

 return !(this.variable == "value")
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  1. Editorial Team
    Editorial Team
    2026-06-04T07:11:06+00:00Added an answer on June 4, 2026 at 7:11 am

    They’re returning true or false based on the opposite of the result of the comparison.

    It would probably have been clearer to write:

    return this.variable != "value";
    

    Sometimes you see:

    return !!(some.expression);
    

    which forces a “truthiness” conversion of the result of the expression to boolean (true or false). The “!!” is just a pair of individual logical complement (“not”) operators. The first one (on the right) converts the result of the expression to boolean, but the opposite of the “truthiness”. The second therefore flips it back.

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