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Home/ Questions/Q 7879763
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T03:58:40+00:00 2026-06-03T03:58:40+00:00

I am generating json from an xml file using the Newtonsoft dll. From the

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I am generating json from an xml file using the Newtonsoft dll. From the below how would I get the address details into a list(if there were more in the example) and write them to a dropdown list I have the following valid json (checked onjsonlint):

{
    "?xml": {
        "@version": "1.0",
        "@encoding": "utf-8"
    },
    "Root": {
        "Information": {
            "Error": {
                "ErrorNo": "0",
                "ErrorMsg": null
            },
            "Address": {
                "Address": [
                    {
                        "@AddressID": "14961943",
                        "@Sequence": "1",
                        "@Description": "Some Company Name, Some Building, 10 Some Street, Some County, Some City"
                    }            
                ]
            }
        }
    }
}
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  1. Editorial Team
    Editorial Team
    2026-06-03T03:58:42+00:00Added an answer on June 3, 2026 at 3:58 am

    Try this:

    var json = // that object above
    var addresses = json.Root.Information.Address.Address;
    
    for (var i = 0; i < addresses.length; i++) {
        var $option = $("<option></option>").val(addresses[i]["@AddressID"]).text(addresses[i]["@Description"]);
        $("#mySelect").append($option);
    }
    

    Example fiddle

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