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Home/ Questions/Q 6226965
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T09:07:45+00:00 2026-05-24T09:07:45+00:00

i am getting the following regex from a json from server regexval = ^[A-Za-z\\’\\s\\.\\-\\,]{1,50}$

  • 0

i am getting the following regex from a json from server

regexval = ^[A-Za-z\\'\\s\\.\\-\\,]{1,50}$

there is a problem with this regular expression it has a ‘ which is breaking my js code to test this regular expression. how do i make this a valid regex?

im doing something like this to test it

if(!regexval.replace(/\\/g,"\\").test(inputVal)) {
}

EDIT

following is the JSON

[
    {
        "ExtensionData": {},
        "Data1": null,
        "DisplayName": "First Name",
        "IsRequired": true,
        "LengthValidation": 0,
        "Name": "ServiceFirstName",
        "RegexValidation": "^[A-Za-z\\'\\s\\.\\-\\,]{1,50}$",
        "Type": "String",
        "ValidationMessage": "The field 'First Name' doesn't meet the format requirements"
    },
 {
        "ExtensionData": {},
        "Data1": null,
        "DisplayName": "Last Name",
        "IsRequired": true,
        "LengthValidation": 0,
        "Name": "ServiceLastName",
        "RegexValidation": "^[A-Za-z\\'\\s\\.\\-\\,]{1,50}$",
        "Type": "String",
        "ValidationMessage": "The field 'Last Name' doesn't meet the format requirements"
    }
]
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T09:07:46+00:00Added an answer on May 24, 2026 at 9:07 am

    Can you change the single quote to a unicode character /u0027 or use the ASCII \x27 and have it work properly?

    See it in action here: http://jsfiddle.net/TezdR/1/

    SO, really you DON’T need to do the replace but can use the “string” as it is – here is an updated version where you can see I do the replace on FirstName but not on last – and they both should work the same: http://jsfiddle.net/TezdR/2/

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