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Home/ Questions/Q 7775521
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T17:39:08+00:00 2026-06-01T17:39:08+00:00

I am loading an image in python what I think is proper but it

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I am loading an image in python what I think is proper but it still doesn’t display. I don’t know if the image is too big or what.

import pygame
import math

pygame.display.init()
window = pygame.display.set_mode((600, 500))
mapImg = pygame.image.load("mapoftheusa.bmp")

done = False

while not done:

    window.fill((0,0,0))
    evtList = pygame.event.get()
    for evt in evtList:
         if evt.type == pygame.QUIT:
            done = True

    window.blit(mapImg, (0,0)) #<<will not blit

pygame.quit()
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T17:39:10+00:00Added an answer on June 1, 2026 at 5:39 pm

    You forgot to add a call to pygame.display.update() right after window.blit(mapImg, (0,0)).

    So, your complete code should be:

    import pygame
    import math
    
    pygame.display.init()
    window = pygame.display.set_mode((600, 500))
    mapImg = pygame.image.load("mapoftheusa.bmp")
    
    done = False
    
    while not done:
    
       window.fill((0,0,0))
       evtList = pygame.event.get()
       for evt in evtList:
           if evt.type == pygame.QUIT:
              done = True
    
       window.blit(mapImg, (0,0)) #<<will not blit
       pygame.display.update() # solution: you forgot this...
    
    pygame.quit()
    

    pygame.display.update() updates the window (screen) with your drawings. If you dont call it you will not see anything at all. pygame.display.flip() also works, but it should be used when double buffering or hardware surfaces are being used.

    Also, I think it is better to initialize pygame by calling pygame.init() as this will initialize all of its modules including the display.

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