Question

I am looking for a way to grep a file for a specific pattern with negative pattern in it.
I have a log file witch reports units version and I want to see if there is a unit witch report version other then 26.

The closest I could get is :

cat my.log | grep -i -e “version=0x[^2][^6]”

The above return a line contain “version=0x13” but not return a line contain “version=0x23”

Is there a way to tell grep to do so ?

Thanks.

Answer 1

Interpret the pattern as a perl regular expression using the -P switch:

grep -iP 'version=0x(?!26)\d\d' my.log