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Home/ Questions/Q 7817195
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T06:09:11+00:00 2026-06-02T06:09:11+00:00

I am looping through a set of beans and doing a check for something

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I am looping through a set of beans and doing a check for something and adding to a list. I only want to add one occurrence of a particular item

List<PartsBean> beans = hotPartsDAO.getDeletedList(user);
List<FinalItemBean> finalItemList = new ArrayList<FinalItemBean>();
for (PartsBean bean : beans)
{
    if (!bean.getFinalItem().isActive())
    {
        finalItemList.add(bean.getFinalItem());
    }
}

In the list I get for example

"test"
"test"
"test"
"hello"

I just want 1 “test”

If I were to use a set then how would I modify this so that I can add the components of that set to this below:

This here is how its currently being passed over List<FinalItemBean> list

protected final void buildFinalItemFilterList( Action action, PartsDAO dao, List<FinalItemBean> list )

    throws SQLException
{
    List<FinalItemBean> finalItems = dao.getAllFinalItems( false );
    FinalItemBean finalItem;

    for (FinalItemBean e: list )
    {
         finalItem = dao.getFinalItemById(e.getId());
         finalItems.add(finalItem);
    }

    Collections.sort( finalItems );
    action.setRequestAttribute("finalItems", finalItems );
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-02T06:09:13+00:00Added an answer on June 2, 2026 at 6:09 am

    The interface list has a Method called contains, which return a true if that ‘occurrence’ is on the list and a false if is not in the list.
    Like:

    if(!myList.contains(person)) myList.add(person);
    

    Pretty easy. You could also use a Set instead, but, I think lists are more flexible than sets, or that’s what some developers believe.

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