Question

I am new to pointers and I was wondering if someone can take a look at my code and tell me why I am getting an error ” invalid conversion from Char to Char;

#include <iostream>
#include <string>
#include <sstream>

using namespace std;

int main (int argc, char * const argv[]) {
    int stringlenght;
    string  input;

    cout << "Please enter a  string >";
    getline(cin,input);
    cout << "You entered: " << input  << endl << endl;

    stringlenght=input.length();
    cout << stringlenght;

    char *inputArray[stringlenght];
    for (int i=0; i < stringlenght; i ++) {
        inputArray[i]=input[i];
    }

    //system("pause");
}

Answer 1

The problem with your example is that you have declared inputArray as an array of pointers to characters, and therefore inputArray[i] will be a pointer to a character.

What you are trying to do is assign the pointer at the i:th position in inputArray a character value.

What I think you would like to do is to declare inputArray as:

char *inputArray = new char[length];

... your loop ...

delete []inputArray;

This instead creates one pointer, and makes it point to a contigous area in memory where you can store characters, and therefore the type of inputArray[i] will be char instead of char *.