I am new to studying jquery.ajax. Through some tutorials, I tried some code by myself, but I met some trouble. So I ask for help.
I tried to do this: open a.php, send html data from div#send to b.php, then return the data and show in div#result.
a.php
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.4.4/jquery.min.js" type="text/javascript"></script>
<script language="javascript">
$(document).ready(function () {
var params = "value=" + $('#send').text();
$.ajax({
url:'b.php',
type:'post',
dataType:'html',
data:params,
success:data
});
function data (html) {
var str=html.send;
alert(html);
$("#result").html(str);
}
});
</script>
<body>
<div id="result"></div>// I need return 'this is an apple.'
<div id="send">apple</div>
b.php
<?php
echo 'This is an '.$_REQUEST['value'].'.';
?>
To return datas from b.php, you have to do an
echo