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Home/ Questions/Q 5946631
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T16:51:00+00:00 2026-05-22T16:51:00+00:00

I am not using this code in any production environment, it is just for

  • 0

I am not using this code in any production environment, it is just for my understanding. Is this code valid (i.e. can I define my postfix operator like this?):

class A
{
public:
    A& operator++(int n)
    {
        std::cout<<"N is:"<<n<<"\n";
        return *this;
    }
};


int main()
{   
    A a;
    a++;
    a.operator ++(10);
}

On VS2008, I get the output as:

N is 0

for first call and

N is 10

for second call

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T16:51:01+00:00Added an answer on May 22, 2026 at 4:51 pm

    This behavior is legal and well defined in 13.5.7:

    Calling operator++ explicitly, as in
    expressions like a.operator++(2), has
    no special properties: The argument to
    operator++ is 2.

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