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Home/ Questions/Q 514275
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T07:30:28+00:00 2026-05-13T07:30:28+00:00

I am printing an image using an ID which is generated. however i wanted

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I am printing an image using an ID which is generated. however i wanted to do a check to see if this image exists and if it doesnt print no-image.jpg instead…

<img src="phpThumb/phpThumb.php?src=../public/images/'.$row["id"].'/th.jpg&w=162" alt="" width="162" /> 

It would be great if this could be kept on one line is possible. Any help would be appreciated.

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  1. Editorial Team
    Editorial Team
    2026-05-13T07:30:29+00:00Added an answer on May 13, 2026 at 7:30 am

    What Kristopher Ives says, and file_exists:

    echo (file_exists("/path/file/name/here") ? "web/path/goes/here" : "no_image.jpg")
    

    btw, your snippet is unlikely to work, as you seem to be combining plain HTML output and PHP without putting the PHP into <? ?>

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