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Home/ Questions/Q 580883
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T14:31:14+00:00 2026-05-13T14:31:14+00:00

I am rather inexperienced C++ programmer, so this question is probably rather basic. I

  • 0

I am rather inexperienced C++ programmer, so this question is probably rather basic. I am trying to get the file name for my copula:

string MonteCarloBasketDistribution::fileName(char c)
{
    char result[100];
    sprintf(result, "%c_%s(%s, %s).csv", copula.toString().c_str(), left.toString().c_str(), right.toString().c_str());
    return string(result);
}

which is used in:

MonteCarloBasketDistribution::MonteCarloBasketDistribution(Copula &c, Distribution &l, Distribution &r): copula(c), left(l), right(r)
{
    //.....
    ofstream funit;
    funit.open (fileName('u').c_str());

    ofstream freal;
    freal.open (fileName('r').c_str());
}

However, the files created have rubbish names, consisting mainly from weird characters. Any idea what I am doing wrong and how to fix it?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T14:31:14+00:00Added an answer on May 13, 2026 at 2:31 pm

    sprintf has 4 place holders while you give only 3 parameters.

    I would suggest:

    string MonteCarloBasketDistribution::fileName(char c) {
       std::ostringstream result;
       result << c <<"_"<<copula<<'('<<left<<", "<<right<<").csv";
       return result.str();
    }
    

    Your sprintf is not safe for buffer overflow, use rather C99 snprintf or std::stringstream

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