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Home/ Questions/Q 6667627
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T02:57:12+00:00 2026-05-26T02:57:12+00:00

I am studying nachos for a university project and can’t understand what the DEBUG(…)

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I am studying nachos for a university project and can’t understand what the DEBUG(…) statement in the below code is doing.

void
ThreadTest1()
{
   DEBUG('t', "Entering ThreadTest1");
   Thread *t = new Thread("forked thread");
   t->Fork(SimpleThread, 1);
   SimpleThread(0);
}

Can someone please help ?

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  1. Editorial Team
    Editorial Team
    2026-05-26T02:57:13+00:00Added an answer on May 26, 2026 at 2:57 am

    DEBUG is a conditional print statement that is activated when you run your code with “-d” option, as in $nachos -d ti. There are a few debug flags, for example “t” enables printing (debugging) of thread events, which you think you’re after by your code snippet.

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