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Home/ Questions/Q 7998185
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T15:09:02+00:00 2026-06-04T15:09:02+00:00

I am trying to add a key from one table to another so that

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I am trying to add a key from one table to another so that I can create a one to many relationship. The table I would like to add a foreign key to currently has the employee’s first name and last name, but not ID. I would like to query the employee table to find the ID based on their first name and last name, and then add it to the injury table.

I Keep getting the following errors:

The multi-part identifier "InjuryOLD.FirstName" could not be bound.
The multi-part identifier "dbo.InjuryOLD.LastName" could not be bound.

Below is the SQL Statement:

Insert into dbo.InjuryOLD(dbo.InjuryOLD.EmpID)
Select dbo.EmployeeInformation.EmpID
From EmployeeInformation
Where exists(select dbo.EmployeeInformation.EmpID from dbo.EmployeeInformation
             where dbo.EmployeeInformation.FirstName = dbo.InjuryOLD.FirstName 
             and dbo.EmployeeInformation.LastName = dbo.InjuryOLD.LastName)

I have ensured that the tables and columns that I am referencing have no typo’s, and I know that there is a chance that two employee could have the same name. However that is not the case in this scenario.

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  1. Editorial Team
    Editorial Team
    2026-06-04T15:09:04+00:00Added an answer on June 4, 2026 at 3:09 pm

    The SELECT part an INSERT statement should always work on its own

    so…

    Select dbo.EmployeeInformation.EmpID
    From EmployeeInformation
    Where exists(select dbo.EmployeeInformation.EmpID from dbo.EmployeeInformation
                 where dbo.EmployeeInformation.FirstName = dbo.InjuryOLD.FirstName 
                 and dbo.EmployeeInformation.LastName = dbo.InjuryOLD.LastName)
    

    …doesn’t work because dbo.InjuryOLD isn’t referenced in either FROM clause. You probably meant to put the dbo.InjuryOLD in the from clause of the Exists sub query instead of repeating EmployeeInformation

    Select dbo.EmployeeInformation.EmpID
    From EmployeeInformation
    Where exists(select 1 from dbo.InjuryOLD  
                 where
                     dbo.EmployeeInformation.FirstName = dbo.InjuryOLD.FirstName 
                     and dbo.EmployeeInformation.LastName = dbo.InjuryOLD.LastName)
    
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