Question

I am trying to convert a char to an int that’s passed to a method:

volume('10');

void volume(char* number) {
  for (int i = 0; i < atoi(number); i++) {
    // do something 10 times
  }
}

This doesn’t seem to be working.

Answer 1

Change:

volume('10');

void volume(char* number) {
  for (int i = 0; i < atoi(number); i++) {
    // do something 10 times
  }
}

to:

volume("10"); // <<< note the double quotes !

void volume(const char* number) { // <<< note the const
  for (int i = 0; i < atoi(number); i++) {
    // do something 10 times
  }
}

NB: if you had compiled with warnings enabled (e.g. gcc -Wall ...) then the above errors would have been immediately apparent. Try to get into the habit of doing this and do not ignore warnings – they are there for a good reason and will often save you a lot of time debugging problems at run-time that could have been fixed at compile-time.