Question

I am trying to convert an integer number in C into an array containing each of that number’s digits

i.e. if I have

int number = 5400 

how can I get to

int numberArray[4] 

where

numberArray[0] = 0; numberArray[1] = 0; numberArray[2] = 4; numberArray[3] = 5; 

Any suggestions gratefully received.

Answer 1

This would work for numbers >= 0

#include <math.h>  char * convertNumberIntoArray(unsigned int number) {     int length = (int)floor(log10((float)number)) + 1;     char * arr = new char[length];     int i = 0;     do {         arr[i] = number % 10;         number /= 10;         i++;     } while (number != 0);     return arr; } 

EDIT: Just a little bit more C style but more cryptic.

#include <math.h>  char * convertNumberIntoArray(unsigned int number) {     unsigned int length = (int)(log10((float)number)) + 1;     char * arr = (char *) malloc(length * sizeof(char)), * curr = arr;     do {         *curr++ = number % 10;         number /= 10;     } while (number != 0);     return arr; }