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Asked: May 11, 20262026-05-11T04:21:46+00:00 2026-05-11T04:21:46+00:00

I am trying to convert an IStream to HBITMAP using the GDI+ Bitmap class.

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I am trying to convert an IStream to HBITMAP using the GDI+ Bitmap class. The IStream object is being populated by using data from a web service. I am reading the data in parts and appending it to an object to be used later with the Bitmap class.

Here is the relevant part of the code

        char data1[] = '';         int offset = 0;          LPTSTR pszString = NULL;         LPSTREAM lpStream = NULL;          CreateStreamOnHGlobal(NULL, TRUE, &lpStream);         StreamStringCopy ((LPSTREAM)lpStream, (LPCTSTR)'');         while(of->pread(&data1,1023,offset) > 0){             LPCTSTR tempStr = data1;             StreamStringCat ((LPSTREAM)lpStream, tempStr);             offset = offset + strlen(data1);             }         Bitmap bm(lpStream,FALSE);         bm.GetHBITMAP(Color.Black, &ret); 

StreamStringCat appends the string to the LPSTREAM object so I can get a single LPSTREAM object.

The loop runs fine only the first time. When the while loop is entered again, the &data1 gives an Access violation exception.

Can someone please tell me how I should resolve this issue. Thanks.

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  1. 2026-05-11T04:21:47+00:00Added an answer on May 11, 2026 at 4:21 am

    First, be careful with string literals. String literals like '' are of type const char*, so you cannot write to them. I’m not entirely sure whether your construct char data1[] = '' makes it writable, but even if so, you have only memory for 2 characters there, while you (I suppose) try to read 1023 bytes into the location of data1. Try this:

    char* data1 = static_cast<char*> (std::malloc (1024 * sizeof (char));  ...  std::free (data1);  // or try this char data1 [1024] = { 0 }; // Gives you 1024 bytes to write to on the stack 

    This allocates some memory, which can be written to. I guess after the first run, you’ve overwritten some memory, which leads to the access violation in the next run.

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