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Home/ Questions/Q 6906381
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T08:18:09+00:00 2026-05-27T08:18:09+00:00

I am trying to create a histogram with the following code and entering in

  • 0

I am trying to create a histogram with the following code and entering in a large dataframe

sortDATA<-function(name)
{
  #sort the code by session Id, first name, then last name
  sort1.name <- name[order("sessionid","qf","qn") , ]

  #create a vector of length of first names
  sname<-nchar(sort1.name$qf)

  hist(sname)
}

My histogram is empty. Any idea of what I am doing wrong with this code?

I am adding some of the sample data

               sessionid             qf        qn         city
1  9cf571c8faa67cad2aa9ff41f3a26e38     cat   biddix          fresno
2  e30f853d4e54604fd62858badb68113a   caleb     amos                
3  2ad41134cc285bcc06892fd68a471cd7  daniel  folkers                
4  2ad41134cc285bcc06892fd68a471cd7  daniel  folkers                
5  63a5e839510a647c1ff3b8aed684c2a5 charles   pierce           flint
6  691df47f2df12f14f000f9a17d1cc40e       j    franz prescott+valley
7  691df47f2df12f14f000f9a17d1cc40e       j    franz prescott+valley
8  b3a1476aa37ae4b799495256324a8d3d  carrie mascorro            brea
9  bd9f1404b313415e7e7b8769376d2705    fred  morales       las+vegas
10 b50a610292803dc302f24ae507ea853a  aurora      lee                
11 fb74940e6feb0dc61a1b4d09fcbbcb37  andrew    price       yorkville
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T08:18:10+00:00Added an answer on May 27, 2026 at 8:18 am

    Instead of :

    sname<-nchar(sort1.name$qf)
    

    try:

    sname<-nchar(as.character(sort1.name$qf))
    

    It seems R might be looking at it as a factor. To check try:

    class(sort1.name$qf)
    

    and see what it tells you. class() can be very helpful due to R’s literal nature about data types and containers.

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