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Asked: 2026-05-20T18:28:16+00:00

I am trying to display all of the records from a database in phpMyAdmin.

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I am trying to display all of the records from a database in phpMyAdmin. This database is located on my computer which is currently a server because of the Uniform Server software installed on it recently. I am new to building php and html code. I used the last compete documenet code from this link http://www.siteground.com/tutorials/php-mysql/display_table_data.htm and this is the output on my web page.

<HTML>

<HEAD>

<TITLE> LOG INFORMATION FOR ALL customers </TITLE>

</HEAD>


<BODY>

<H1> LOG INFORMATION FOR ENTIRE DATABASE </H1>

<?php


$database="mobile_app_tracking_log";

mysql_connect(localhost);
@mysql_select_db($database) or die( "Unable to select database");
$query="SELECT * FROM tablename";
$result=mysql_query($query);



mysql_close();
?>

<table border="2" cellspacing="7" cellpadding="7">
<tr>
<th><font face="Arial, Helvetica, sans-serif">Index</font></th>
<th><font face="Arial, Helvetica, sans-serif">Identification Number</font></th>
<th><font face="Arial, Helvetica, sans-serif">Date</font></th>
<th><font face="Arial, Helvetica, sans-serif">Time</font></th>
<th><font face="Arial, Helvetica, sans-serif">Application</font></th>
<th><font face="Arial, Helvetica, sans-serif">Usage</font></th>
<th><font face="Arial, Helvetica, sans-serif">Latitude</font></th>
<th><font face="Arial, Helvetica, sans-serif">Longitude</font></th>
<th><font face="Arial, Helvetica, sans-serif">Address</font></th>
</tr>

<?php
$i=0;
while ($i < $num) {


$f1=mysql_result($result,$i,"Index");
$f2-name=mysql_result($result,$i,"Identification Number");
$f3-name=mysql_result($result,$i,"Date");
$f4-name=mysql_result($result,$i,"Time");
$f5-name=mysql_result($result,$i,"Application");
$f6-name=mysql_result($result,$i,"Usage");
$f7-name=mysql_result($result,$i,"Latitude");
$f8-name=mysql_result($result,$i,"Longitude");
$f9-name=mysql_result($result,$i,"Address");
?>

<tr>
<td><font face="Arial, Helvetica, sans-serif"><?php echo $f1; ?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><?php echo $f2; ?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><?php echo $f3; ?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><?php echo $f4; ?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><?php echo $f5; ?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><?php echo $f6; ?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><?php echo $f7; ?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><?php echo $f8; ?></font></td>
<td><font face="Arial, Helvetica, sans-serif"><?php echo $f9; ?></font></td>
</tr>


<?php

$i++;
}

?>

Can somebody please tell me why the records from the database aren’t showing? Any help would be much appreciated.

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1 Answer

  1. Editorial Team

    It looks like you are saving the variable $f2-name however you are echo’ing $f2, same with $f3, $f4 etc.

    If you want to keep your naming schema, you have do do:

    echo $f2-name;
echo $f3-name;
// etc
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