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Home/ Questions/Q 6933041
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T11:46:52+00:00 2026-05-27T11:46:52+00:00

I am trying to have an array with n elements permute through like so:

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I am trying to have an array with n elements permute through like so:

permute(x,y,z)
permute(-x,y,z)
permute(x,-y,z)
permute(-x,-y,z)

It is like incrementing in binary (if the – signs represented 1s).
I am attempting to do that in code, and have noticed this:

    list[1] = -list[1];
        perm(list, k, m);
        list[1] = -list[1];
        list[2] = -list[2];
        perm(list, k, m);
        list[1] = -list[1];
        perm(list, k, m);
        list[1] = -list[1];
        list[2] = -list[2];
        list[3] = -list[3];
        perm(list, k, m);
        list[1] = -list[1];
        perm(list, k, m);
        list[1] = -list[1];
        list[2] = -list[2];
        perm(list, k, m);
        list[1] = -list[1];
        perm(list, k, m);
        list[1] = -list[1];
        list[2] = -list[2];
        list[3] = -list[3];
        list[4] = -list[4];
        perm(list, k, m);

I have noticed that some sections repeat. Is there a way to write this into a loop? Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T11:46:53+00:00Added an answer on May 27, 2026 at 11:46 am

    This returns the kth permutation according to your scheme:

    IEnumerable<int> Perm(IEnumerable<int> source, int k)
    {
        return source.Select((x, i) => ((k >> i) & 1) == 1 ? -x : x);
    }
    

    Example:

    var data = new[] { 1, 2, 3, 4 };
    
    for (int k = 0; k < (1 << data.Length); k++)
    {
        Console.WriteLine(string.Join(", ", Perm(data, k)));
    }
    

    Output:

    1, 2, 3, 4
    -1, 2, 3, 4
    1, -2, 3, 4
    -1, -2, 3, 4
    1, 2, -3, 4
    -1, 2, -3, 4
    1, -2, -3, 4
    -1, -2, -3, 4
    1, 2, 3, -4
    -1, 2, 3, -4
    1, -2, 3, -4
    -1, -2, 3, -4
    1, 2, -3, -4
    -1, 2, -3, -4
    1, -2, -3, -4
    -1, -2, -3, -4
    
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