I am trying to run the following code to loop around a recordset and do updates where neccessary.
I have a Microsoft Access database connected to a MySql backend. Whenever I run this code I get the following error:
3197 error: The Microsoft Office Access database engine stopped the process because you and another user are attempting to change the same data at the same time.
The code is below:
Private Sub test()
Dim rs As DAO.Recordset, rsCnt As Long, i As Long
Set rs = CurrentDb.OpenRecordset("qryMyQuery", DB_OPEN_DYNASET)
rs.MoveLast
rsCnt = rs.RecordCount
rs.MoveFirst
For i = 1 To rsCnt
rs.Edit
rs!MyFieldInTable = "test"
rs.Update
Next i
End Sub
I thought the Access database might be corrupt so I pulled an earlier backup but it’s doing the same thing which makes me think it’s a MySql issue.
We use an identical piece of code on another version of this database linked to a different MySql table and it works fine.
Also, when I open the query the record-set is based on I can edit the data in the query without any issues.
Just to add, on the first loop, rs!MyFieldInTable is updated, then I get the error.
It does not appear that you are moving to another record in the recordset. Simply incrementing
idoesn’t move to the next record. A more traditional approach would be to iterate over the recordset without the need for your other variables (iandrsCnt).EDIT
After a bit of searching I came across this thread which seems to be similar to your issue. At the bottom of the thread a suggestion is made to modify the ODBC settings for your MySQL DSN by selecting the “Advanced” tab and selecting the option to “Return Matching Rows”. The post also says to drop the linked table and then re-link it to your Access database.
I haven’t used Access with MySQL in the past, so I have no idea whether this will work or not, so proceed with caution!
You may also try changing your recordset to use the dbOptimistic flag for the recordset locking option to see if that helps at all:
set rs = CurrentDB.OpenRecordSet("qryMyQuery", DB_OPEN_DYNASET, dbOptimistic)