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Home/ Questions/Q 6870889
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T03:44:18+00:00 2026-05-27T03:44:18+00:00

I am trying to set the value in an array to a variable. Here

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I am trying to set the value in an array to a variable. Here is my code:

//init the array as a float
//I have tried to put a value in the brackets, but it returns a different error.
//I initialized it this way so I could call it from other methods
private float[] map;

// generate a "seed" for the array between 0 and 255
float x = generator.nextInt(256);
int n = 1;
// insert into the first 25 slots
while(n <= 25) {
    // here's my problem with this next line
    map[n] = x;
    double y = generator.nextGaussian();
    x = (float)Math.ceil(y);
    n = n + 1;
}

I marked the line with my error, the error returned is: “uncaught exception thrown in…”. What am I doing wrong??? Thanks in advance.

EDIT—–

Here’s the whole exception:

    Uncaught exception thrown in Thread[LWJGL Renderer Thread,5,main]

I’m using y to generate a random gaussian, then converting it into a float value and changing x into that float value

I’m pretty sure that It’s that line, because that’s what my compiler told me.

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  1. Editorial Team
    Editorial Team
    2026-05-27T03:44:19+00:00Added an answer on May 27, 2026 at 3:44 am

    I’m guessing that you get one of two exceptions:

    1. You are getting a NullPointerException because have initialized map to null. Assign a non-null value using for example:

      private float[] map = new float[25];
      
    2. You are getting an IndexOutOfBoundsException because you are using 1-based indexing instead of 0-based indexing.

    Change this:

    int n = 1;
    while(n <= 25) {
        // etc..
        n = n + 1;
    }
    

    To this for loop:

    for (int n = 0; n < 25; ++n) {
        // etc..
    }
    
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