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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T11:10:05+00:00 2026-05-20T11:10:05+00:00

I am trying to split a large xml file into several smaller files. I

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I am trying to split a large xml file into several smaller files. I found a solution to split each node into it’s own file:

awk '/<mono/{close("row"count".xml");count++}count{f="row"count".xml";print $0 > f}' file.xml 

The above code matches every “mono” node and outputs it to a file names row{rownumber}.xml. How can I print every 20 matches to a file?

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  1. Editorial Team
    Editorial Team
    2026-05-20T11:10:06+00:00Added an answer on May 20, 2026 at 11:10 am

    I would say keep your “count” variable, and you just need to change the way you build your filename: f="row" int(count/20) ".xml"

    You don’t have to explicitly close the file. All open files will be closed when awk exits. Given the comments, I’ll strike that remark. Note in the code below, a file will be closed up to 20 times, but reopened as required.

    awk '
      /<mono/ {close f; count++; f = "row" int(count/20) ".xml"} 
      count {print >> f}
    ' file.xml
    
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