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Home/ Questions/Q 4018632
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T10:00:25+00:00 2026-05-20T10:00:25+00:00

I am trying to understand STL algorithms. Copy is defined as : template<class InputIterator,

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I am trying to understand STL algorithms.

Copy is defined as :

template<class InputIterator, class OutputIterator>
  OutputIterator copy ( InputIterator first, InputIterator last, OutputIterator result )

Can some one please explain why does the following works when vectors & deques are mixed but fails when vectors and sets are mixed.

#include <iostream>
#include <algorithm>
#include <vector>
#include <deque>
#include <deque>
#include <set>
using namespace std;

int main () {
  int myints[]={10,20,30,40,50,60,70};
  vector<int> myvector;
  vector<int>::iterator it;

  set<int> mset(myints,myints+8);
  set<int>::iterator setItr = mset.begin();




  deque<int> deq;
  deq.resize(10);
  deque<int>::iterator deqItr = deq.begin();
  myvector.resize(7);   // allocate space for 7 elements
  copy ( myints, myints+7, myvector.begin() );

  copy ( myvector.begin(), myvector.end(), deqItr );
  cout << "deque contains:";
  for (deque<int>::iterator dit=deq.begin(); dit!=deq.end(); ++dit)
    cout << " " << *dit;

  cout << endl;

  //copy ( myvector.begin(), myvector.end(), setItr );


  return 0;
}

I understand vectors/deque have random access iterators, where as set’s have bidirectional iterators. I fail to understand why compilation fails when only a input/output iterators are required.

PS : This is just an experiment to increase my understanding 🙂

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  1. Editorial Team
    Editorial Team
    2026-05-20T10:00:26+00:00Added an answer on May 20, 2026 at 10:00 am

    Associative containers (in plain C++03) are special containers that keep their elements sorted at all times, commonly implemented as a Red Black Tree. To maintain the order invariant, the set and map iterators provide constant references into the key object, and as such you cannot modify it.

    In particular for std::set<T>, the iterator will usually be such that std::iterator_traits< std::set<T>::iterator >::reference is const T&, and as such the assignment implicit in the std::copy operation will fail.

    If what you want to do is insert the elements into a set, you can use iterators from the <iterator> header that will perform insert operations in the set:

    std::copy( v.begin(), v.end(), std::inserter( s, s.end() ) ); // s is the set
    
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