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Asked: May 11, 20262026-05-11T10:04:33+00:00 2026-05-11T10:04:33+00:00

I am trying to use a return type of const MyClass * const .

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I am trying to use a return type of const MyClass * const. However, I get a warning:

Warning: #815-D: type qualifier on return type is meaningless.

Is this not a valid type? I want a pointer than cannot be changed, and I want the thing it points to to not be changed either.

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  1. 2026-05-11T10:04:34+00:00Added an answer on May 11, 2026 at 10:04 am

    The pointer itself has value type, so it doesn’t make sense to make it const. What the caller function does with the returned value can’t be restricted by the called function. This is akin to trying to define something like:

    const int getInt(); 

    getInt(), in this case, just returns an int value (not a reference). It goes to a register, then the caller function receives it and does whatever it wants with it.

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  • added an answer This code might be your solution http://snippets.dzone.com/posts/show/3532 May 11, 2026 at 2:42 pm
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