Question

I am trying to write 4 integers to a single byte.

In the example below is I can unpack \x11 and then read the bits (answer = 1 2 0 0) but how would I do the reverse? i.e. how would I pack 1 2 0 0 into \xll

import struct

val = struct.unpack('B', '\x11')[0]

a = val & 7
b = (val >> 3) & 7
c = (val >> 6) & 1
d = (val >> 7)

print a, b, c, d

I am pretty new to all this… many thanks!

Answer 1

Like this:

val = ((d & 1) << 7) | ((c & 1) << 6) | ((b & 7) << 3) | (a & 7)