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Home/ Questions/Q 8701329
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T02:22:19+00:00 2026-06-13T02:22:19+00:00

I am trying to write a batch file for Windows 7 that will create

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I am trying to write a batch file for Windows 7 that will create 100 text files with names – ex1 to ex100. In each file i need to replace a given text (eg. ex3) with the same text as the name of the file.

So far I have managed to get the batch file to create the 100 files however the text (ex3) is replaced by ex1 in each file.

Here is the code that I have used. I am a complete novice to this and have cobbled it together from bits that I have found.

@echo off
setlocal enabledelayedexpansion

FOR /F "usebackq delims=" %%G IN ("c:\batch\batch.txt") DO (
  Set Line=%%G
  Set Line=!Line:"='!
  Call:replace "!Line!"
)

pause


goto:eof ------------
  :replace subroutine
  (Set Line=%*&Set Line=!Line:~1,-1!)
  Set Line=!Line:'="!

For /l %%A in (7,1,100) do Set "Line=!Line:ex3=ex%%A!"  
For /l %%n in (1,1,100) do echo.!Line! >>"c:\batch\ex%%n.txt"

 goto:eof ------------

Any suggestions?

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  1. Editorial Team
    Editorial Team
    2026-06-13T02:22:21+00:00Added an answer on June 13, 2026 at 2:22 am

    Wow – that code is way more convoluted than is needed (and also slow because of CALL).

    @echo off
    setlocal enableDelayedExpansion
    set "folder=c:\batch"
    for /l %%N in (1 1 100) do del "%folder%\ex%%N.txt" 2>nul
    for /f "usebackq delims=" %%A in ("%folder%\batch.txt") do (
      set "line=%%A"
      for /l %%N in (1 1 100) do (echo !line:ex3=ex%%N!)>>"%folder%\ex%%N"
    )
    
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