Question

I am trying to write a program by running Django using manage.py runserver ip:port in my Linux box as a non-root user. My first objective is that if a user enters a URL in the browser http://ip:port it should display something or a welcome content.

So I modified my mysite/url.py something like this:

urlpatterns = patterns('',
    ('', ''),
    (r'^admin/', include(admin.site.urls)),
)

python manage.py runserver : runs and start fine but in browser I get below exception:

Exception Type: ImproperlyConfigured
Exception Value: Empty URL pattern view name not permitted (for pattern ”)

So how can construct the URL just like:

www.google.com
www.mail.yahoo.com
www.mysite.com

Thanks in advance

Answer 1

The empty pattern will match anything, so you should be anchoring it to full empty string. The second tuple parameter must also be a view name.

In your URLconf:

urlpatterns = patterns('',
    (r'^$', 'views.home'),     # ^$ means, beginning of string followed by end of string, in other words match on exactly empty string and nothing else
    (r'^admin/', include(admin.site.urls)),
)

In a views.py in the same directory:

from django.http import HttpResponse

def home(request):
    return HttpResponse('Hello World')