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Home/ Questions/Q 7562025
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T13:18:37+00:00 2026-05-30T13:18:37+00:00

I am trying to write an operator != function that compares if two complex

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I am trying to write an operator != function that compares if two complex numbers are the same. I Have written an equal to == function which works well but I am trying to use the negation of the result.

bool ComplexNumber::operator !=(ComplexNumber a) {
    return !(this==(a));  //the == has been overloaded
}
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  1. Editorial Team
    Editorial Team
    2026-05-30T13:18:39+00:00Added an answer on May 30, 2026 at 1:18 pm

    return !(this==(a)); is comparing a ComplexNumber* to a ComplexNumber. Change to:

    bool ComplexNumber::operator !=(const ComplexNumber& a) const {
        return !(*this == a);  //the == has been overloaded
    }
    

    Also added const qualifier to function and argument (which I changed to to a reference to avoid unnecessary copy). You will need to add const qualifier to bool ComplexNumber::operator ==() if it is not already present.

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