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Asked: 2026-05-16T07:41:18+00:00

I am used to oracle and now been thrown T-SQL, I am doing a

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I am used to oracle and now been thrown T-SQL, I am doing a course shortly but can you help out until then.

I have a list that I need to group in minutes.

Sample of rowdate data

SELECT ROWDATE,count(rowdate)
FROM [mydb].[dbo].[mytable]
GROUP BY ROWDATE
order by 1

2010-08-16 15:01:18.110 1
2010-08-16 15:01:18.203 1
2010-08-16 15:01:18.377 1
2010-08-16 15:01:18.453 1
2010-08-16 15:01:18.530 1
2010-08-16 15:01:18.610 1
2010-08-16 15:01:18.703 1
2010-08-16 15:01:18.813 1
2010-08-16 15:01:18.953 1
2010-08-16 15:01:19.173 1
2010-08-16 15:01:19.360 1
2010-08-16 15:01:19.483 1
2010-08-16 15:01:19.593 1
2010-08-16 15:01:19.673 1
2010-08-16 15:01:19.733 1
2010-08-16 15:01:19.813 1
2010-08-16 15:01:19.890 1
2010-08-16 15:01:19.970 1
2010-08-16 15:01:20.047 1

I just want to group by mins. 

SELECT to_char(rowdate,'dd/MM/yyyy HH24:MI'),count(rowdate)
FROM mytable
GROUP BY to_char(rowdate,'dd/MM/yyyy HH24:MI')
order by 1

On sql server(T-SQL) what would be the equivalent script?

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1 Answer

  1. Editorial Team

    to floor the datetime down to the minute use (which is better than using string manipulations):

    DATEADD(minute,DATEDIFF(minute,0,datetime),0)

    so, to group by minutes, it would be:

    SELECT 
    DATEADD(minute,DATEDIFF(minute,0,ROWDATE),0)
    ,count(rowdate)
FROM [mydb].[dbo].[mytable]
GROUP BY DATEADD(minute,DATEDIFF(minute,0,ROWDATE),0)
order by 1
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