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Home/ Questions/Q 186397
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Asked: May 11, 20262026-05-11T15:38:23+00:00 2026-05-11T15:38:23+00:00

I am using a mysqli prepard query with php, the code is: $retreiveQuery =

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I am using a mysqli prepard query with php, the code is:

$retreiveQuery = 'SELECT username, firstname, lastname FROM USERS WHERE username = ?';  if ($getRecords = $con->prepare($retreiveQuery)) {     $getRecords->bind_param('s', $username);      $getRecords->execute();             $getRecords->bind_result($username, $firstname, $lastname);  echo '<h1>'.$username.'</h1> <p><strong>First Name: </strong>'.$firstname.' <p><strong>Surname: </strong>'.$lastname.' } else { print_r($con->error); 

This is quite strange. username is the only field which is displayed. Why would the other columns not be being returned/bound?

If I do

SELECT username, firstname, lastname FROM USERS WHERE username = 'test'; 

Directly to the database, all fields are displayed, and all contain valid data.

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  1. 2026-05-11T15:38:24+00:00Added an answer on May 11, 2026 at 3:38 pm

    You have to call

    $getRecords->fetch(); 

    after bind_result() to actually get the record.

    Username was being output because you had already set it, to use as an input parameter.

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