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Home/ Questions/Q 7632087
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T06:31:47+00:00 2026-05-31T06:31:47+00:00

I am using following jQuery code to submit a form via AJAX. jQuery(‘form.AjaxForm’).submit( function()

  • 0

I am using following jQuery code to submit a form via AJAX.

jQuery('form.AjaxForm').submit( function() {            
        $.ajax({
            url     : $(this).attr('action'),
            type    : $(this).attr('method'),
            dataType: 'json',
            data    : $(this).serialize(),
            success : function( data ) {
                        alert('Submitted')
                      },
            error   : function( xhr, err ) {
                        alert(''Error);     
                      }
        });    
        return false;
    });

Code is working perfectly with no ajax. But does not work if I load form via ajax. I think it is because of loading form via ajax after JavaScript load.

Any solution?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T06:31:48+00:00Added an answer on May 31, 2026 at 6:31 am

    If using jQuery 1.7+ you could try using .on() to delegate the event and bind to all future forms with the same class.
    Try finding the closest parent that is not inserted dynamicly instead of $(document).

    $(document).on('submit', 'form.AjaxForm', function() {            
            $.ajax({
                url     : $(this).attr('action'),
                type    : $(this).attr('method'),
                dataType: 'json',
                data    : $(this).serialize(),
                success : function( data ) {
                             alert('Submitted');
                },
                error   : function( xhr, err ) {
                             alert('Error');     
                }
            });    
            return false;
        });
    
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