Question

I am using thread which will receive messages from the
external application.So my thread shud be alive always.

I want my thread to be running through out the application,
untill application exits. Currently i am calling my thread in program.cs,
which is the startup for windows application c#. Please see the code below
to know how i am doing it.

When i use the below code, the thread starts up when
application starts…But it aborts some how, after the thread recieves
one message from the external application.

I hope i am clear with my questio. Please help. Thanks.

---

  static void Main()
    {
        Application.EnableVisualStyles();
        Application.SetCompatibleTextRenderingDefault(false);
        StartThread();
        Application.Run(new Screensaver());
    }
    public static void StartThread()
    {
            DeamonEngine Deamon = new DeamonEngine();
            Thread ThreadReciever = new Thread(Deamon.Receiver);
            if (!(ThreadReciever.IsAlive))
            {
                ThreadReciever.Start();
            }
        }
    }

---

From a comment:

    void Receiver() { 
        try { 
            Initiate socket s; 
            Bind Ip address; 
            s.Receiver[bytes]; 
            Access the members of message received in bytes;
            Assign the members of message to local variable;
            Read Xml File, get the node values and write to batch file; 
            Execute batch file. 
        } 
        catch { } 
    }

Answer 1

Having a thread execute the Receiver method doesn’t mean the thread will repeatedly execute the method.

Given the processing code in the question, Daemon.Receiver needs to execute in a loop so that it can go back and retrieve the next message to process. It should look something like this:

void Receiver() { 
    while(!done) // without this loop, only one execution will occur
    {
        try { 
            // do stuff
        } 
        catch { 
            // log/handle error
        } 

        // wait for next message
    }
}