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Home/ Questions/Q 8426905
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T04:39:20+00:00 2026-06-10T04:39:20+00:00

I am working on a php mysql connect script. I wanted it to use

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I am working on a php mysql connect script.
I wanted it to use functions so I can keep a track what is what, so Mysql connect got one function.
When I run it, I get first “No database selected” and when I specify it manually, it says “Access denied for @ localhost”.

Code

<?php
/* Mysql Data */
$MySqlUser = "root";
$MySqlPass = "**********";
$MySqlHost = "localhost";
$MySqlDataBase = "serveradmin";
/* End Mysql Data */
function MySqlConnect() {
    $Connect = mysql_connect($MySqlHost, $MySqlUser, $MySqlPass);
    $Database = mysql_select_db($MySqlDataBase);
    if (!$Connect | !$Database) {
        die("Cannot connect ".mysql_error());
    }
}
MySqlConnect()
?>

So the problem, what causes this? I want the script to be nice and clean, and not sure if function() causes it.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T04:39:22+00:00Added an answer on June 10, 2026 at 4:39 am

    This will fix it, but please look into PDO or mysqli

    <?php
    /* Mysql Data */
    $MySqlUser = "root";
    $MySqlPass = "**********";
    $MySqlHost = "localhost";
    $MySqlDataBase = "serveradmin";
    /* End Mysql Data */
    function MySqlConnect($MySqlUser, $MySqlPass, $MySqlHost, $MySqlDataBase ) {
        $Connect = mysql_connect($MySqlHost, $MySqlUser, $MySqlPass);
        $Database = mysql_select_db($MySqlDataBase);
        if (!$Connect | !$Database) {
            die("Cannot connect ".mysql_error());
        }
        return $Database;
    }
    $Database = MySqlConnect($MySqlUser, $MySqlPass, $MySqlHost, $MySqlDataBase );
    ?>
    
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