Question

I can make a variable’s name from two variables’ value:

$a = 'tea';
$b = 'pot';
$tea_pot = 'Too Hot';

Here if I print or echo ${$a.'_'.$b}, I will get ‘Too Hot’ as output.

Similarly I need to make an array’s name from two variables’ value.
I try this the code below. But it’s giving me an error: Undefined variable.

I want something like:
$k = ${'B'.$a} where $a=5 and $B5 = array('c', 'v', 'b');
and want to echo($k[2]);

the codes that i want to solve is here…

$B0 = array('apple', 'crow', 'monkey', 'lion', 'deer', 'bear', 'tiger');
$B1 = array('bad', 'meaningless', 'odd', 'no fare', 'poor', 'old', 'dirty', 'damn', 'rush');
function($set, $number){
     while($set >= 2){
          $set -= 2;
     }
     if($set == 0){
          while($number >= 7){
               $numbur -= 7;
          }
     } else {
          while($number >= 9){
               $numbur -= 9;
          }
     }
     $array = ${'B'.$set}; // Error
     return $array[$number];
}
/*Error: it is saying that here the "${'B'.$set}" is a Undefined variable
where it is a name of an array. what can I do to realize
that it is not a variable but an array.*/

Answer 1

I got the real problem and its solve…
Here the arrays “B0” and “B1” are places outside the function so you have to declare the ${‘B’.$set} as a global array by just adding a single line inside the function before you call it. Like this:

$B0 = array('apple', 'crow', 'monkey', 'lion', 'deer', 'bear', 'tiger');
$B1 = array('bad', 'meaningless', 'odd', 'no fare', 'poor', 'old', 'dirty', 'damn', 'rush');
function($set, $number){
     while($set >= 2){
          $set -= 2;
     }
     if($set == 0){
          while($number >= 7){
               $numbur -= 7;
          }
     } else {
          while($number >= 9){
               $numbur -= 9;
          }
     }
     global ${'B'.$set};
     $array = ${'B'.$set};
     return $array[$number];
}

now it will understand and will get the array properly and will not show any errors.