Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7727013
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 1, 20262026-06-01T05:21:12+00:00 2026-06-01T05:21:12+00:00

i can’t figure out about working with I/O. I am using this code to

  • 0

i can’t figure out about working with I/O.

I am using this code to read from file:

if (file.length() > Integer.MAX_VALUE) {
    throw new IllegalArgumentException("File is too large: " + file.length());
}

int len = (int) file.length();
System.out.println("failo dydis yra = "+len);
FileInputStream inputStream = new FileInputStream(file);

try {
    byte[] fileBits = new byte[len];
    for (int pos = 0; pos < len;) {
        int n = inputStream.read(fileBits, pos, len - pos);

        if (n < 0) {
            throw new EOFException();
        }
        pos += n;

    }
    for(int q=0; q<len; q++){
        char ch = (char)fileBits[q];
        int sk = (int)ch;
        System.out.println("symbol = "+fileBits[q]+" - "+ch+" - "+sk);
    }

When i read txt file then everything is nice but when i read not txt for example image i get similar result:

symbol = -78 - ᄇ - 65458
symbol = 52 - 4 - 52
symbol = -91 - ᆬ - 65445
symbol = 80 - P - 80
symbol = -118 - ハ - 65418
symbol = 76 - L - 76
symbol = 122 - z - 122
symbol = 78 - N - 78
symbol = 112 - p - 112
symbol = 97 - a - 97
symbol = 56 - 8 - 56
symbol = -112 - ミ - 65424

So i can’t figure why there are minus ? And why when i want to convert back i get this 65***.

Maybe i have to read different if i want to convert these bytes to chars, work with them and write again to file.

Thanks.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-01T05:21:14+00:00Added an answer on June 1, 2026 at 5:21 am

    So i can’t figure why there are minus ?

    In Java, a byte can have values between -128 and 127. Therefore, you’re seeing negative values. You can use 0xff & fileBits[q] to convert that to an integer value between 0 and 256.

    And why when i want to convert back i get this 65***

    Converting a byte into a char is meaningless unless the byte happens to be part of a string of ASCII characters in an ASCII-compatible encoding. What happens is that Java extends the byte’s first bit to a 16bit value. If the first bit happens to be set (i.e. the number is negative), the result will be a high 16 bit number, typically in the form of 65xxx.

    Everything is working fine, just give the bytes to an image processing/display function. Note that your function is error-prone since it will needlessly fail if the file size changes while you’re reading the file. If you want to read a string, use a Reader object, for example an InputStreamReader.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Can't figure out how to do this in a pretty way : I have
Can somebody help me with this. There is HTML code: <h3> <label> <input type=checkbox
Can I figure out if a function has already been assigned to an event?
I'm new to using the Perl treebuilder module for HTML parsing and can't figure
can someone explain why the compiler accepts only this code template<typename L, size_t offset,
Can't work out a way to make an array of buttons in android. This
Can anyone help me trying to find out why this doesn't work. The brushes
Can we close all known/unknown connections to database with the code? I'm using Access
Can I convert a pdf to pcl file with ghostscript? I'm using Ghostscript 9.01
Does anyone know how can I replace this 2 symbol below from the string

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.