Question

I can’t figure out why this doesn’t work, please help!! I just get the message “decoded =”

mydata = JSON.stringify(array_str_idnum);

$.ajax({
type:           'post',
cache:          false,
url:            'parser.php',
data:           mydata,
datatype:       'json',
success: function(msg){
         $("#formstatus").ajaxComplete(function(){$(this).html(msg)});
           }        
});

---

<?php

// decode JSON string to PHP object
$decoded = json_decode($_POST['myJson'],true);

echo "decoded =";
echo $decoded;

?>

Answer 1

As @Reanimation suggests, you need to send the parameter that will hold the JSON data. I would recommend doing it more JavaScriptish way as:

$.ajax({
    type: 'post',
    cache: false,
    url: 'parser.php',
    data: {'myJson': mydata},
    datatype: 'json',
    success: function(msg){
            $("#formstatus").ajaxComplete(function(){$(this).html(msg)});
    }        
});

The other thing is that $decoded will actually hold an array as long as the original array_str_idnum is array, so doing echo $decoded will output Array(). Note also that the second paramerter to json_decode is to return the objects as associative arrays.