Question

I can’t find anywhere it has been documented this. By default, the find() operation will get the records from beginning. How can I get the last N records in mongodb?

Edit: also I want the returned result ordered from less recent to most recent, not the reverse.

Answer 1

If I understand your question, you need to sort in ascending order.

Assuming you have some id or date field called “x” you would do …

.sort()

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db.foo.find().sort({x:1});

The 1 will sort ascending (oldest to newest) and -1 will sort descending (newest to oldest.)

If you use the auto created _id field it has a date embedded in it … so you can use that to order by …

db.foo.find().sort({_id:1});

That will return back all your documents sorted from oldest to newest.

Natural Order

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You can also use a Natural Order mentioned above …

db.foo.find().sort({$natural:1});

Again, using 1 or -1 depending on the order you want.

Use .limit()

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Lastly, it’s good practice to add a limit when doing this sort of wide open query so you could do either …

db.foo.find().sort({_id:1}).limit(50);

or

db.foo.find().sort({$natural:1}).limit(50);