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Home/ Questions/Q 4040500
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T12:45:38+00:00 2026-05-20T12:45:38+00:00

I can’t quite figure this one out. To make it simple I’ll explain what

  • 0

I can’t quite figure this one out. To make it simple I’ll explain what I’m trying to do.

Currently, I am working on a nHibernate project which uses a repository pattern. Inside the database are a bunch of tables that have “Description” fields. Now, I am trying to localize these tables to use a common “Resource” table.

So, I have these 2 tables:

Table 1 – Resources :
ResourceId, LanguageId, Value

Table 2 – LinkLabels :
LinkLabelId, Description, ResourceId

Then there is a session token that contains a “LanguageId” which is the preferred language of the user.

Okay, with that said, what I need to do is get the “Value” from the ResourcesTable where ResourceId from LinkLabels = ResourceId from Resources for objects that have a “ResourceId”. But I’ve got to do this with a Generic type.

Here is what I have so far:

public IQueryable<T> ToQueryable<T>()
{
    try
    {
        PropertyInfo resourceProperty = typeof(T).GetProperty("ResourceKey");

        if (resourceProperty != null)
        {
            // Somthing like this, but of course this won't work
            // because x.ResourceId doesn't exist because of generic, and the select
            // statement is invalue.
            //
            // return from x in this.session.Query<T>()
            //        join p in this.session.Query<Resource>() on x.ResourceId equals p.ResourceId
            //        where p.LanguageId = 1 // this will be from a session object, hardcoded to 1 for now
            //        select x where x.Description is p.value;
        }
        else
        {
            return this.session.Query<T>();
        }
    }
    catch (Exception ex)
    {
        throw ex;
    }
}
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  1. Editorial Team
    Editorial Team
    2026-05-20T12:45:39+00:00Added an answer on May 20, 2026 at 12:45 pm

    Create an interface like this:

    interface IResource {
    int ResourceId { get; set;}
    }

    Then use a constraint:

    public IQueryable ToQueryable() where T: IResource
    {
    …
    }

    Then you have to make all your types implement IResource as well.

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