Question

I can’t seem to work it out. I am using a .c code that opens a file and reads each line. I would like to save in char*substr 4 characters from the line 9 inside the txt file. The line 5 contains
name=Me She; I would like to have in char*substr just Meli.Need help. THX
Here is the c code:

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
  FILE *fp;
  char str[128];
char str1[128];

  if((fp = fopen("/home/folder/file.txt", "r"))==NULL) {
    printf("Cannot open file.\n");
    exit(1);
  }

int lin=0;
  while(!feof(fp)) {
    if(fgets(str, 126, fp)) 
        printf("%s", str);
        if (lin==8)
        {
            char *c= (char *) malloc(sizeof(char)*strlen(str)+1);

            c= strndup(str, strlen(str)-5);?? not working?!!!
            printf("d is:",c);
        }

        lin=lin+1;
  }

  fclose(fp);

  return 0;
}

Answer 1

Your printf is wrong. change it to printf("d is %s\n",c);.

By the way, strdup allocate the memory needed, so you don’t have to allocate it yourself. (In fact, you have a memory leak).